-x^+6x^2-12x-35=0

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Solution for -x^+6x^2-12x-35=0 equation:



-x^+6x^2-12x-35=0
We add all the numbers together, and all the variables
6x^2-13x-35=0
a = 6; b = -13; c = -35;
Δ = b2-4ac
Δ = -132-4·6·(-35)
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{1009}}{2*6}=\frac{13-\sqrt{1009}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{1009}}{2*6}=\frac{13+\sqrt{1009}}{12} $

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